Optimal. Leaf size=120 \[ \frac{a^2 (2 A+3 B+2 C) \sin (c+d x)}{2 d}+\frac{1}{2} a^2 x (4 A+3 B+2 C)+\frac{a^2 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{(3 B+2 C) \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{6 d}+\frac{C \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
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Rubi [A] time = 0.343351, antiderivative size = 120, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {3045, 2976, 2968, 3023, 2735, 3770} \[ \frac{a^2 (2 A+3 B+2 C) \sin (c+d x)}{2 d}+\frac{1}{2} a^2 x (4 A+3 B+2 C)+\frac{a^2 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{(3 B+2 C) \sin (c+d x) \left (a^2 \cos (c+d x)+a^2\right )}{6 d}+\frac{C \sin (c+d x) (a \cos (c+d x)+a)^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 3045
Rule 2976
Rule 2968
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int (a+a \cos (c+d x))^2 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec (c+d x) \, dx &=\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{\int (a+a \cos (c+d x))^2 (3 a A+a (3 B+2 C) \cos (c+d x)) \sec (c+d x) \, dx}{3 a}\\ &=\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{(3 B+2 C) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{\int (a+a \cos (c+d x)) \left (6 a^2 A+3 a^2 (2 A+3 B+2 C) \cos (c+d x)\right ) \sec (c+d x) \, dx}{6 a}\\ &=\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{(3 B+2 C) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{\int \left (6 a^3 A+\left (6 a^3 A+3 a^3 (2 A+3 B+2 C)\right ) \cos (c+d x)+3 a^3 (2 A+3 B+2 C) \cos ^2(c+d x)\right ) \sec (c+d x) \, dx}{6 a}\\ &=\frac{a^2 (2 A+3 B+2 C) \sin (c+d x)}{2 d}+\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{(3 B+2 C) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\frac{\int \left (6 a^3 A+3 a^3 (4 A+3 B+2 C) \cos (c+d x)\right ) \sec (c+d x) \, dx}{6 a}\\ &=\frac{1}{2} a^2 (4 A+3 B+2 C) x+\frac{a^2 (2 A+3 B+2 C) \sin (c+d x)}{2 d}+\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{(3 B+2 C) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{6 d}+\left (a^2 A\right ) \int \sec (c+d x) \, dx\\ &=\frac{1}{2} a^2 (4 A+3 B+2 C) x+\frac{a^2 A \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^2 (2 A+3 B+2 C) \sin (c+d x)}{2 d}+\frac{C (a+a \cos (c+d x))^2 \sin (c+d x)}{3 d}+\frac{(3 B+2 C) \left (a^2+a^2 \cos (c+d x)\right ) \sin (c+d x)}{6 d}\\ \end{align*}
Mathematica [A] time = 0.311171, size = 121, normalized size = 1.01 \[ \frac{a^2 \left (3 (4 A+8 B+7 C) \sin (c+d x)-12 A \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+12 A \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+24 A d x+3 (B+2 C) \sin (2 (c+d x))+18 B d x+C \sin (3 (c+d x))+12 C d x\right )}{12 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.059, size = 181, normalized size = 1.5 \begin{align*}{\frac{A{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{3\,{a}^{2}Bx}{2}}+{\frac{3\,{a}^{2}Bc}{2\,d}}+{\frac{5\,{a}^{2}C\sin \left ( dx+c \right ) }{3\,d}}+2\,A{a}^{2}x+2\,{\frac{A{a}^{2}c}{d}}+2\,{\frac{{a}^{2}B\sin \left ( dx+c \right ) }{d}}+{\frac{{a}^{2}C\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{d}}+{a}^{2}Cx+{\frac{{a}^{2}Cc}{d}}+{\frac{A{a}^{2}\sin \left ( dx+c \right ) }{d}}+{\frac{{a}^{2}B\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{C\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}{a}^{2}}{3\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.992002, size = 207, normalized size = 1.72 \begin{align*} \frac{24 \,{\left (d x + c\right )} A a^{2} + 3 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{2} + 12 \,{\left (d x + c\right )} B a^{2} - 4 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{2} + 6 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{2} + 12 \, A a^{2} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 12 \, A a^{2} \sin \left (d x + c\right ) + 24 \, B a^{2} \sin \left (d x + c\right ) + 12 \, C a^{2} \sin \left (d x + c\right )}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.05267, size = 269, normalized size = 2.24 \begin{align*} \frac{3 \,{\left (4 \, A + 3 \, B + 2 \, C\right )} a^{2} d x + 3 \, A a^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, A a^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) +{\left (2 \, C a^{2} \cos \left (d x + c\right )^{2} + 3 \,{\left (B + 2 \, C\right )} a^{2} \cos \left (d x + c\right ) + 2 \,{\left (3 \, A + 6 \, B + 5 \, C\right )} a^{2}\right )} \sin \left (d x + c\right )}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.30885, size = 317, normalized size = 2.64 \begin{align*} \frac{6 \, A a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 6 \, A a^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + 3 \,{\left (4 \, A a^{2} + 3 \, B a^{2} + 2 \, C a^{2}\right )}{\left (d x + c\right )} + \frac{2 \,{\left (6 \, A a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 9 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 6 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 12 \, A a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 24 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 16 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 6 \, A a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 15 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 18 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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